1. Write a query to display the last name, department number, and salary of any employee whose department number and salary both match the department number and salary of any employee who earns a commission. 2. Display the last name, department name, and salary of any employee whose salary and commission match the salary and commission of any employee located in location ID1700. 3. Create a query to display the last name, hire date, and salary for all employees who have the same salary and commission as Kochhar. Note: Do not display Kochhar in the result set. 4. Create a query to display the employees who earn a salary that is higher than the salary of all of the sales managers (JOB_ID = ’SA_MAN’). Sort the results on salary from highest to lowest. 5. Display the details of the employee ID, last name, and department ID of those employees who live in cities whose name begins with T. 6. Write a query to find all employees who earn more than the average salary in their departments. Display last name, salary, department ID, and the average salary for the department. Sort by average salary. Use aliases for the columns retrieved by the query as shown in the sample output. 7. Find all employees who are not supervisors. a. First do this by using the NOT EXISTS operator. b. Can this be done by using the NOT IN operator? How, or why not? 8. Write a query to display the last names of the employees who earn less than the average salary in their departments. 9. Write a query to display the last names of employees who have one or more coworkers in their departments with later hire dates but higher salaries. 10. Write a query to display the employee ID, last names, and department names of all employees. Note: Use a scalar subquery to retrieve the department name in the SELECT statement. 11. Write a query to display the department names of those departments whose total salary cost is above one-eighth (1/8) of the total salary cost of the whole company. Use the WITH clause to write this query. Name the query SUMMARY.